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Contents contributed and discussions participated by David Kim

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Quiz 3 - 14 views

started by Jyoti Pakianathan on 03 Apr 13 no follow-up yet
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Quiz 2 Post your answers with steps here - 15 views

started by Jyoti Pakianathan on 03 Apr 13 no follow-up yet
  • David Kim
    #4 David Kim on 06 Apr 13
     
    Circumference - Minor Arc = Major Arc

    Minor Arc
    = 45/360 x 3(3.14)
    = 1/8 x 9.42
    = 1.1775

    Circumference
    = 3(3.13)
    = 9.42

    Major Arc
    = 9.42 - 1.1775
    = 8.2425

Trapezoids - 32 views

started by Bethany Parks on 20 Feb 13 no follow-up yet
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Kite Activity - 20 views

started by Bethany Parks on 19 Feb 13 no follow-up yet
  • David Kim
    #7 David Kim on 20 Feb 13
     
    Kite is created with two distinct pairs of adjacent congruent sides.

Unit 8 - 27 views

started by Jyoti Pakianathan on 03 Feb 13 no follow-up yet
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Unit 8 - 34 views

started by Jyoti Pakianathan on 03 Feb 13 no follow-up yet
  • David Kim
    #3 David Kim on 05 Feb 13
     
    8-1
    1. C) E and G
    2. C) FM and NM
    3. D) HJ and IK
    4. A) 110
    5. C) 70

    5/5

Vectors - 11 views

started by Jyoti Pakianathan on 29 Jan 13 no follow-up yet
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Homework Pythagoras triads - 13 views

started by Jyoti Pakianathan on 25 Jan 13 no follow-up yet
  • David Kim
    #3 David Kim on 27 Jan 13
     
    Every odd number greater than 1 can be the lowest number in a Pythagorean Triad
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question 8 - 24 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #3 David Kim on 26 Jan 13
     
    Height of the Pole = x
    Length of the shadow = x√3

    Imaginary side connecting the tip of the pole and the end of the shadow = 2x
    Because it is a 30,60,90 special right triangle

    Therefore the angle elevation of the sun = 30

question 7 - 29 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
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question 6 - 24 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #2 David Kim on 25 Jan 13
     
    tan(x) = 2√3/2
    x = tan-1(2√3/2)
    Angle of Elevation = 60
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question 5 - 27 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #3 David Kim on 25 Jan 13
     
    tan(60) = x/40
    tan(60)x40 = x
    x = 69.282

    tan(30) = y/40
    tan(30)x40 = y
    y = 23.094

    Height of 2nd tower = 69.282 - 23.094
    =46.188
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question 4 - 26 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #3 David Kim on 25 Jan 13
     
    tan(60) = 28/x
    28/tan(60) = x
    x = 16.1658

    tan(45) = 28/y
    28/tan(45) = y
    y = 28

    Distance between the 2 men = 28 + 16.1658
    =44.17
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question 3 - 32 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #2 David Kim on 25 Jan 13
     
    tan(60) = 120/x
    120/tan(60) = x
    x = 69.282

    tan(30) = 120/y
    120/tan(30) = y
    y = 207.846

    Distance between the 2 men = 207.846 - 69.282
    =138.564m
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question 2 - 27 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
  • David Kim
    #4 David Kim on 25 Jan 13
     
    sin(30) = 18/x
    18/sin(30) = x
    x=36
    length of string = 36m

question 1 - 31 views

started by Jyoti Pakianathan on 24 Jan 13 no follow-up yet
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