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Jyoti Pakianathan

question 6 - 24 views

started by Jyoti Pakianathan on 24 Jan 13
  • Jyoti Pakianathan
     
    If the height of a pole is 2√3 metres and the length of its shadow is 2 metres,
    find the angle of elevation of the sun.
  • David Kim
     
    tan(x) = 2√3/2
    x = tan-1(2√3/2)
    Angle of Elevation = 60
  • kwonteddy17
     
    tan-1(2√3/2) = x
    x=60
  • Elaine Kim
     
    tan-1 (2√3/2) = x
    x = 60
    Elevation of sun = 60
  • Haley Park
     
    tan x= 2√3/2.
    2√3/2.=1.73

    tan-1*1.73= 59.97

    The elevation of the sun= 59.97
  • backchanyel17
     
    tan-1(2√3/2)= angle of elevation
    answer= 60
  • Alex Kim
     
    Tan-1 (2√3/2) = 60
  • anonymous
     
    Tan (x) = 2 root 3 / 2
    Tan-1 (2 root 3 / 2) = x

    Answer: 60 meters
  • Sally Rho
     
    tan x=2√3/2
    2√3/2=1.73
    tan-1(2√3/2)=x
    x=60
  • Janice Min
     
    Tan-1 (2√3/2)
    angle of elevation = 60
  • Harine Choi
     
    tan x = 2√3/2
    x = 60
  • Jason Kim
     
    tan x = 2√3 over 2
    inverse tan 2√3 over 2

    x= 60

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