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Jyoti Pakianathan

question 5 - 27 views

started by Jyoti Pakianathan on 24 Jan 13
  • Jyoti Pakianathan
     
    Two towers face each other separated by a distance d = 40 m. As seen from the top of the first tower, the angle of depression of the second tower's base is 60o and that of the top is 30o. What is the height (in meters) of the second tower?
  • kwonteddy17
     
    tan(30) times 40 = 23.094

    tan(60) times 40 = 69.282

    69.282 - 23.094 = 46.188 h
  • David Kim
     
    tan(60) = x/40
    tan(60)x40 = x
    x = 69.282

    tan(30) = y/40
    tan(30)x40 = y
    y = 23.094

    Height of 2nd tower = 69.282 - 23.094
    =46.188
  • Haley Park
     
    tan 60= x/40
    tan 60*40=x
    x= 69.282

    tan 30= y/40
    tan 30*40=y
    y=23.1

    69.282-23.1=46.188
  • backchanyel17
     
    tan(60)x40 - tan(30)x40= Height of the second tower
    =46.188
  • Elaine Kim
     
    tan 60 = x/40
    tan 60*40 = x
    x= 69.282

    tan 30 = x/40
    tan 30*40 = x
    y= 23.094

    69.282 - 23.094
    = 46.188 (Height)
  • Alex Kim
     
    x = 69

    y = 23

    69-23 = 46
  • Nam Hyun Kim
     
    tan(30) * 40 = 23.094
    tan(60) * 40 = 69.282
    = 46.188
  • anonymous
     
    Tan (60) = x/40
    Tan (60)x40 = x
    x = 69.282m

    Tan (30) = y/40
    Tan (30) x 40 = y
    y = 23.094

    Answer:
    =46.188meters
  • Sally Rho
     
    tan60=x/40
    y=tan60X40
    x=69.282

    tan30=x/40
    y=tan30X40
    y=23.094

    69.282-23.094
    =46.188
  • choandy17
     
    Tan(30) = y/40
    y= 23.094

    Tan(60) = x/30
    x=69.282

    x-y=
    69.282 - 23.094 = 46.188
  • trey noh
     
    46.188
  • Janice Min
     
    tan60=x/40
    tan60X40=x
    x=69.282

    Tan30=y/40
    tan30X40=y
    y=23.094

    69.282-23.094=46.188

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