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Structure and randomness in the prime numbers « What's new - 0 views

  • 2 July, 2008 at 6:28 pm Terence Tao It unfortunately seems that the decomposition claimed in equation (6.9) on page 20 of that paper is, in fact, impossible; it would endow the function h (which is holding the arithmetical information about the primes) with an extremely strong dilation symmetry which it does not actually obey. It seems that the author was relying on this symmetry to make the adelic Fourier transform far more powerful than it really ought to be for this problem.
  • 3 July, 2008 at 3:41 am Gergely Harcos I also have some (perhaps milder) troubles with the proof. It seems to me as if Li had treated the Dirac delta on L^2(A) as a function. For example, the first 5 lines of page 28 make little sense to me. Am I missing something here?
  • 4 July, 2008 at 5:15 am Lior Silberman The function defined on page 20 does have a strong dilation symmetry: it is invariant by multiplication by ideles of norm one (since it is merely a function of the norm of ). In particular, it is invariant under multiplication by elements of . I’m probably missing something here. Probably the subtlety is in passing from integration over the nice space of idele classes to the singular space . The topologies on the spaces of adeles and ideles are quite different. There is a formal error in Theorem 3.1 which doesn’t affect the paper: the distribution discussed is not unique. A distribution supported at a point is a sum of derivatives of the delta distribution. Clearly there exist many such with a given special value of the Fourier transform. There is also something odd about this paper: nowhere is it pointed out what is the new contribution of the paper. Specifically, what is the new insight about number theory?
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  • 4 July, 2008 at 6:09 am Emmanuel Kowalski A remark concerning Lior’s remark: the function h(u) in the current (v4) version of the paper is _not_ the same as the one that was defined when T. Tao pointed out a problem with it. This earlier one (still visible on arXiv, v1) was defined in different ways depending on whether the idele had at most one or more than one non-unit component, and was therefore not invariant under multiplication by . (It is another problem with looking at such a paper if corrections as drastic as that are made without any indication of when and why).
  • 4 July, 2008 at 8:15 am Terence Tao Dear Lior, Emmanuel is correct. The old definition of h was in fact problematic for a large number of reasons (the author was routinely integrating h on the idele class group C, which is only well-defined if h was -invariant). Changing the definition does indeed fix the problem I pointed out (and a number of other issues too). But Connes has pointed out a much more serious issue, in the proof of the trace formula in Theorem 7.3 (which is the heart of the matter, and is what should be focused on in any future revision): the author is trying to use adelic integration to control a function (namely, h) supported on the ideles, which cannot work as the ideles have measure zero in the adeles. (The first concrete error here arises in the equation after (7.13): the author has made a change of variables on the idele class group C that only makes sense when u is an idele, but u is being integrated over the adeles instead. All subsequent manipulations involving the adelic Fourier transform Hh of h are also highly suspect, since h is zero almost everywhere on the adeles.)
  • More generally, there is a philosophical objection as to why a purely multiplicative adelic approach such as this one cannot work. The argument only uses the multiplicative structure of , but not the additive structure of k. (For instance, the fact that k is a cocompact discrete additive subgroup of A is not used.) Because of this, the arguments would still hold if we simply deleted a finite number of finite places v from the adeles (and from ). If the arguments worked, this would mean that the Weil-Bombieri positivity criterion (Theorem 3.2 in the paper) would continue to hold even after deleting an arbitrary number of places. But I am pretty sure one can cook up a function g which (assuming RH) fails this massively stronger positivity property (basically, one needs to take g to be a well chosen slowly varying function with broad support, so that the Mellin transforms at Riemann zeroes, as well as the pole at 1 and the place at infinity, are negligible but which gives a bad contribution to a single large prime (and many good contributions to other primes which we delete).)
  • Emmanuel Kowalski That’s an interesting point indeed, if one considers that the RH doesn’t work over function fields once we take out a point of a (smooth projective) curve — there arise zeros of the zeta function which are not on the critical line.
  • 6 July, 2008 at 5:28 pm Chip Neville Terence, I have a question about your comment: “Because of this, the arguments would still hold if we simply deleted a finite number of finite places v from the adeles (and from k^*). … (basically, one needs to take g to be a well chosen slowly varying function with broad support, so that the Mellin transforms at Riemann zeroes, as well as the pole at 1 and the place at infinity, are negligible but which gives a bad contribution to a single large prime (and many good contributions to other primes which we delete).)” Does this mean that you would be considering the “reduced” (for lack of a better name) zeta function \prod 1/(1-1/p^{-s}), where the product is taken over the set of primes not in a finite subset S? If so, this “reduced” zeta function has the same zeroes as the standard Riemann zeta function, since the finite product \prod_S 1/(1-1/p^{-s}) is an entire function with no zeroes in the complex plane. Thus the classical situation in the complex plane seems to be very different in this regard from the situation with function fields over smooth projective curves alluded to by Emmanuel above. Does anyone have an example of an infinite set S and corresponding reduced zeta function with zeroes in the half plane Re z > 1/2? A set S of primes p so that \sum_S 1/p^{1/2} converges will not do, since \prod_S 1/(1-1/p^{-s}) is holomorphic in the half plane Re z > 1/2 with no zeroes there. Perhaps a set S of primes P thick enough so that \sum_S 1/p^{1/2} diverges, but thin enough so that \sum_S 1/p converges, might do. This seems to me to be a delicate and difficult matter. I hope these questions do not sound too foolish.
  • 6 July, 2008 at 7:44 pm Terence Tao Dear Chip, Actually, the product has a number of poles on the line , when s is a multiple of . Li’s approach to the RH was not to tackle it directly, but instead to establish the Weil-Bombieri positivity condition which is known to be equivalent to RH. However, the proof of that equivalence implicitly uses the functional equation for the zeta function (via the explicit formula). If one starts deleting places (i.e. primes) from the problem, the RH stays intact (at least on the half-plane ), but the positivity condition does not, because the functional equation has been distorted.
  • The functional equation, incidentally, is perhaps the one non-trivial way we do know how to exploit the additive structure of k inside the adeles, indeed I believe this equation can be obtained from the Poisson summation formula for the adeles relative to k. But it seems that the functional equation alone is not enough to yield the RH; some other way of exploiting additive structure is also needed, but I have no idea what it should be. [Revised, July 7:] Looking back at Li’s paper, I see now that Poisson summation was indeed used quite a few times, and in actually a rather essential way, so my previous philosophical objection does not actually apply here. My revised opinion is now that, beyond the issues with the trace formula that caused the paper to be withdrawn, there is another fundamental problem with the paper, which is that the author is in fact implicitly assuming the Riemann hypothesis in order to justify some facts about the operator E (which one can think of as a sort of Mellin transform multiplier with symbol equal to the zeta function, related to the operator on ). More precisely, on page 18, the author establishes that and asserts that this implies that , but this requires certain invertibility properties of E which fail if there is a zero off of the critical line. (A related problem is that the decomposition used immediately afterwards is not justified, because is merely dense in rather than equal to it.)
  • 7 July, 2008 at 9:59 am javier Dear Terence, I am not sure I understand your “philosophical” complain on using only the multiplicative structure and not the additive one. This is essentially the philosophy while working over the (so over-hyped lately) field with one element, which apparently comes into the game in the description of the Connes-Bost system on the latest Connes-Consani-Marcolli paper (Fun with F_un). From an algebraic point of view, you can often recover the additive structure of a ring from the multiplicative one provided that you fix the zero. There is an explanation of this fact (using the language of monads) in the (also famous lately) work by Nikolai Durov “A new approach to Arakelov geometry (Section 4.8, on additivity on algebraic monads). By the way, I wanted to tell you that I think you are doing an impressive work with this blog and that I really enjoy learning from it, even if this is the very first time I’ve got something sensible to say :-)
  • 7 July, 2008 at 11:01 am Terence Tao Dear Javier, I must confess I do not understand the field with one element much at all (beyond the formal device of setting q to 1 in any formula derived using and seeing what one gets), and don’t have anything intelligent to say on that topic. Regarding my philosophical objection, the point was that if one deleted some places from the adele ring A and the multiplicative group (e.g. if k was the rationals, one could delete the place 2 by replacing with the group of non-zero rationals with odd numerator and denominator) then one would still get a perfectly good “adele” ring in place of A, and a perfectly good multiplicative group in place of (which would be the invertible elements in the ring of rationals with odd denominator), but somehow the arithmetic aspects of the adeles have been distorted in the process (in particular, Poisson summation and the functional equation get affected). The Riemann hypothesis doesn’t seem to extend to this general setting, so that suggests that if one wants to use adeles to prove RH, one has to somehow exploit the fact that one has all places present, and not just a subset of such places. Now, Poisson summation does exploit this very fact, and so technically this means that my objection does not apply to Li’s paper, but I feel that Poisson summation is not sufficient by itself for this task (just as the functional equation is insufficient to resolve RH), and some further exploitation of additive (or field-theoretic) structure of k should be needed. I don’t have a precise formalisation of this feeling, though.
  • 7 July, 2008 at 1:22 pm Gergely Harcos Dear Terry, you are absolutely right that Poisson summation over k inside A is the (now) standard way to obtain the functional equation for Hecke L-functions. This proof is due to Tate (his thesis from 1950), you can also find it in Weil’s Basic Number Theory, Chapter 7, Section 5.
  • Babak Hi Terrance, A few months ago I stumbled upon an interesting differential equation while using probability heuristics to explore the distribution of primes. It’s probably nothing, but on the off-chance that it might mean something to a better trained mind, I decided to blog about it: http://babaksjournal.blogspot.com/2008/07/differential-equation-estimating.html -Babak
  • 15 July, 2008 at 7:57 am michele I think that the paper of Prof. Xian-Jin Li will be very useful for a future and definitive proof of the Riemann hypothesis. Furthermore, many mathematics contents of this paper can be applied for further progress in varios sectors of theoretical physics (p-adic and adelic strings, zeta strings).
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科学网-王永晖的博客-国内领袖科学家不上本科生课的行政原因 - 0 views

  • 博主回复:诶,奇怪了,怎么会这样,我曾经推算过,如果中国大学实行三学期制,时间是可以安排出来,跟春节-元宵节,中秋节,正好都能避开。 按每学期12周算: 如2009-1-21是春节 2008年中秋节是2008-9-14,在此之间安排第1学期。可取 2008-10-20为开学日,12周之后,2009-01-11结束。 冬假五周后,元宵节过后,第2学期 2009-02-23开学,12周之后,2009-05-17结束。 春假一般不用放的时间长,2周即可,期间正好包含端午节。 第3学期 2009-06-1开学,12周之后,2009-08-23结束。 暑假,放到2009-10-03中秋节之后,具体开学时间,仍然依此理,保证在2010年春节2010-02-15前完成。譬如可取2008-11-02.我这个安排,不是唯一,可能还可以前后挪动1、2周。 所以,感觉以春节-元宵节、端午节、中秋节定位,完全可以排出来3学期制。上海大学不知是怎么做的,但如果跨春节,太违反人性了,肯定效果会大打折扣。西方人是以圣诞节来定位,我们是以春节-元宵节和中秋节定位,所以我们的三学期正好跟美国的三学期有个时间差,这个时间差其实也是个优点,正好方便彼此的教授们,去对方讲学、访学。
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中国高等研究院"数学、理论物理和哲学杰出青年才俊免费班"招生启事-恒甫学社-搜狐博客 - 0 views

  • 中国高等研究院 2008年“数学、理论物理和哲学杰出青年才俊免费班”招生启事     中国高等研究院将从2008年9月开始,每个周末(周六、日)举办数学、理论物理和哲学杰出青年才俊班,讲授数学、理论物理和哲学领域的基础理论。该班为免费授课,欢迎全国各高校的大学生、硕士研究生报名,也欢迎博士研究生参加。   授课时间:每周六、日,第一次课程将于2008年9月6日、7日开始。   授课地点:中央财经大学校内   所授课程涵盖如下领域:   数学:代数,分析,几何,拓扑学; 理论物理:弦论,宇宙学,现象学; 哲学:数理逻辑,分析哲学,心灵哲学,哲学史,中西比较哲学。   授课教授:   数学和理论物理: 沈维孝(讲座教授,东京大学数学博士), 夏志宏(讲座教授,西北大学数学博士),刘清越 (副教授,中国科学院数学博士),郭光远(副教授,牛津大学数学博士,微分几何,拓扑),邓健 (副教授,布朗大学数学博士),徐栩(副教授,中国科技大学博士),梁湘三(教授,哈佛大学博士),杨海棠(副教授,MIT理论物理博士),吕宏(讲座教授,德州A&M大学理论物理博士)等。
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科学网-北京计划引进杰出人才 学科首席专家年薪达百万 - 0 views

  • 意见指出,2008年—2012年在市属高等学校设置10个学科首席专家岗位、40个特聘教授岗位、100个讲座教授岗位,设立50个左右校外名师讲学资助点。学科首席专家岗位主要设置在国家级、教育部及北京市重点学科、重点实验室、研究基地、工程研究中心,学科首席专家可获得总额为2000万元科学研究支持经费,根据工作需要,分年度核拨,享受学科首席专家工资每年100万元;特聘教授岗位一般设在国家重点学科、北京市重点学科及重点建设学科、主干学科以及经济社会发展有重大需求的前沿学科或新兴交叉学科,特聘教授在聘请学校全职工作,在全职工作期间享受特聘教授工资每年10万元;讲座教授岗位的设置不受学科限制,由高等学校根据教学科研工作的需求聘请,讲座教授在聘请学校全职工作时间一年不得少于3个月,在全职工作期间享受讲座教授工资每月1万元。
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Google 阅读器 - 0 views

  • Conference update, part II
  •  
    上午4:41(12 小时前) 我的网站被黑掉了-- 怎么办? 从 Google 黑板报 -- Google 中国的博客网志 作者:joydandan 转载自谷歌中文网站管理员博客 发表者:Nathan Johns,搜索质量组 原文:My site's been hacked - now what? 发表于: 2008年4月7日,星期一,11:37AM 许多网站管理员都有过这样的遭遇:尽管您绞尽脑汁防止此类事情发生,您的网站还是被黑掉了。一些防患于未然的措施包括确保您的网站及时更新最新的软件和补丁,在谷歌网站管理员工具里建立账号以便查看当前被收录的页面,密切注视您的日志文件,确保其中没有可疑的内容等等。(在我们去年发布的"网站安全快速检查清单"里您可以查看到更加详细的信息。) 请记住,您决不是唯一的受害者--网站被黑的情况变得越来越常见。网站被黑会导致您的站点感染有害软件(更具体地说就是恶意软件,这是有害软件的一种类型)。您可以阅读一下StopBadware最近发布的2007年有害软件趋势报告,这篇报告全面分析和总结了近几年来不良软件的发展趋势及其危害。您还可以看看这篇发表在谷歌在线安全博客上的文章,它指出,越来越多的搜索结果中包含着被标为对用户计算机有害的URL。如果您希望阅读有关基于Web的恶意软件的深度分析报告,请您通过下载阅读《浏览器里的幽灵》(pdf) 和这篇技术报告 (pdf) 。读完这些报告后,您会对这些问题的影响范围有更好的理解。这些报告还包括了一些不同类型恶意软件的真实案例。 在任何情况下,你应该采取的第一步措施都是联系您的主机托管供应商--如果您有的话。多数情况下他们都会为您解决很多技术上的麻烦。许多站长使用共享主机托管,但这样可能会使得下面我们提到的一些措施难以实施。在如
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北京大学新生奖学金最高额度5万元_新闻中心_新浪网 - 0 views

  • 清华已宣布新生最高可获4万元奖学金,
  • 北大这次将新生奖学金最高额度由1.6万提高到5万元
  • 新生全额奖学金:总金额5万元/生;新生半额奖学金:总金额2.5万元/生;新生优秀奖学金:总金额1万元/生
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全球首个对华裔中学生数学奖丘成桐奖诞生 - 综合资讯 - 无锡太湖明珠,第一门户网 - 0 views

  • 据介绍,丘成桐中学数学奖其国际评审委员会由权威性极高的海内外著名数学家组成。该奖项启动后将在海内外分五大赛区展开赛程。该奖项将采用美国“西屋科学奖”的组织与选拔模式,要求参赛团队自行寻找研究题目及资料,包括基础研究、商业应用和工程设计等,鼓励创新、实践和团队精神,激发青少年在数学和其它科学研究领域中的潜能。
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日本推出新式养生运动 可纠正老人脊椎歪曲症状_新闻中心_新浪网 - 0 views

  • 日本养生学家最近推出四项运动:金鱼运动、毛细血管运动、合蹠(zhí)合掌运动以及背腹运动等。可以纠正老年人脊椎的歪斜、弯曲;可以促进血液回流,改善微循环通路,使心脏回流量及搏出量增加。   金鱼运动 仰卧,身体伸成一条直线,两脚尖自然向上,两手交叉重叠放在第四颈椎部位,像金鱼的样子身体左右水平摇动。动作要稍快些,每日早晚各做一次,每次一二分钟。   毛细血管运动 仰卧,头枕硬枕,两手、两足垂直高举,然后缓慢抖动,每次最少一二分钟。此运动可促进全身血液循环和淋巴液的回流,提高心脏、肾脏的机能。   合蹠合掌运动 仰卧,两手相合置于胸部,两手指尖合并,膝盖弯曲,两脚尖合并形成合蹠合掌。合掌后两前臂顺长轴上下活动,下肢亦顺长轴活动,合蹠合掌上下伸屈运动36~100次,做完后手掌与脚底合拢,静躺5分钟。   背腹运动 坐姿,手自然放在膝上,躯干挺直,重心落在尾骨上,身体左右摇晃,在不受呼吸影响的前提下,脊柱左右倾斜的同时,腹肌也收缩、松弛交替。一分钟50次左右,做10分钟。
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专家分析汶川地震可能与天文因素有关_新闻中心_新浪网 - 0 views

  •   大地震日期恰好发生在上弦(农历四月初八)。这天,上弦时刻出现在中午11时47分。上弦时,太阳、地球和月球排列成一个直角三角形;从地球上看,太阳和月球的角度恰好等于90度,上弦这天,有来自两个不同方向的引潮力对地球施加影响。历史上有些大地震出现在上弦或下弦的前后:如里氏9.1级的美国阿拉斯加大地震,发生在1957年3月9日(农历二月初八),这天恰好是上弦;里氏8.8级的南美洲厄瓜多尔大地震,发生在1906年1月31日(农历正月初七),次日为上弦;里氏8级的我国甘肃古浪大地震,出现在1927年5月23日(农历四月廿三),次日为下弦;里氏7.3级的我国辽宁省海城县大地震,出现在1975年2月4日(农历十二月廿四),下弦为2月3日。
  •  据广东天文学会表示,今年6月初,有两个强天文潮汐值得有关方面注意。一个出现在6月3日21时,这时月球距离地球最近,只有357251公里,这是2007年11月24日以来月球与地球相距最近的时刻;另一个是6月4日凌晨3时23分,太阳、月球和地球排列成一条直线(朔)。如果这两个强天文潮汐的时间间隔较长,那只属于一般的孤立的天文现象,但它俩相距只有6个小时,将会形成叠加的强天文潮汐,就有可能对地球的气体潮(大气潮)、液体潮(海洋潮)和固体潮(地壳潮)产生显著影响。目前,四川汶川里氏8级大地震后,还存在地壳板块错动,还有余震能量释放不彻底等因素的存在。因此,6月4日前后,这两个强天文潮汐相继出现,值得地震工作者和相关部门关注。来源:南方日报
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温州大学城市学院由学生任大一班主任引争议_新闻中心_新浪网 - 0 views

  • 高校班主任一直是个值得探讨的话题,他们不似小学、高中的班主任,能手把手地言传身教。一些高年级的学生甚至抱怨,读了几年大学,跟班主任说话没超过三句。而高校班主任多为任课老师,且兼有学校各类事务,他们对此也很无奈:“没那么多精力兼顾。再说大学生都是成年人,没必要管得太严。
  • 王定福认为,这还是一种“榜样教育法”,是高校管理的有效补充。“另外对这些小斑竹而言,给了他们一个锻炼的平台,是学校培养高素质应用人才的一种创新。”王定福认为此举可取得双赢局面。(记者胡建国 通讯员孙亚男)
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Akshay Venkatesh - Wikipedia, the free encyclopedia - 0 views

  • Akshay Venkatesh (born November 21, 1981 in New Delhi, India) is an Australian mathematician of Indian descent who was a Clay Research Math Fellow research at the Clay Mathematics Institute from 2004 to 2006.
  • He is currently an associate professor at the Courant Institute of Mathematical Sciences at New York University [11]. As of September 1, 2008, he has been appointed a professor at Stanford University.
  • Venkatesh commenced his PhD at Princeton University in 1998 under Peter Sarnak,
  • ...1 more annotation...
  • whilst aged only 11
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Math 152: Number Theory, Autumn 2008 - 0 views

  • There is no mandatory book for the course. One recommendation is Niven, Zuckerman, and Montgomery's An Introduction to the Theory of Numbers. Hardy and Wright's book of the same name is a classic. Other useful books are LeVeque's Fundamentals of Number Theory, and Stark's An introduction to number theory. Copies of these books have been placed on reserve in the Math library.
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《从一岁上常青藤》导读_薛涌:反智的书生_新浪博客 - 0 views

  • 为了说明这一点,我们不妨检讨一下美国高等教育最近的发展。众所周知,哈佛大学在过去几年,一直给家庭年收入在六万美元以下的孩子免费上哈佛的机会,2007年底又突然宣布:进一步减免中高产阶层的教育费用。从2008年起,年收入在十二万到十八万美元的家庭,只需用家庭收入的十分之一支付子女上哈佛的费用(包括学费、杂费、和食宿费)。十二万以下的家庭则支付的比例更小。有人算了一笔账:如果哈佛彻底实行免费教育(即包了学生的学费、杂费、和食宿费)的话,等于一年放弃了十五亿美元的收入。但是,哈佛2006年自己的“小金库”(即所谓的“捐助基金”)在股市中的回报就是将近七十亿美元。这十五亿对哈佛实在是九牛一毫。另一方面,美国的有关法律规定,各种基金会必须每年花掉基金的5%以上才能享受非赢利组织的免税待遇,但大学的捐助基金不在此列。国会目前正在讨论有关立法,要把大学涵盖在这5%的规矩之内。哈佛的捐助基金达350亿美元,2006年增值23%,但目前每年仅花掉4.3%,离5%的要求还相差甚远,需要想办法把钱花出去。其他常青藤也都大同小异。所以,《华尔街日报》上有人预测,用不了多久,年收入二十万美元以下的家庭,也就是美国95%以上的家庭,送孩子上常青藤这样的一流学府会免费。但是,一般的大学没有这样的捐助基金,财政困难,不得不开源节流,雇用临时教师削减费用,同时增加学费填补财政赤字,可能造成教育质量下降、费用提高。结果可能会出现一个奇怪的现象:上最好的大学免费,上次好的大学便宜,上差的大学反而最贵。这就好比豪华的“悍马”免费,普通的日本车便宜,土造的国产小排放辆最贵。
  • 另外,我通过一系列颇为权威的经验实证研究,展示了一些流行的智力开发不仅无法提高孩子的智商,反而阻碍了孩子的智力发展,并特别指出了过早开始阅读训练的坏处,希望家长警觉。
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2008.11.18)北京出手四万亿的经济分析_张五常Steven N.S. Cheung_新浪博客 - 0 views

  • 我自己认为最不妥的,是把穷人集中在一起,对儿童的心理与成长有不良影响──虽然我教过几位出自廉租房的学生很不错。
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What might an expository mathematical wiki be like? « Gowers's Weblog - 0 views

  • trick, that can be used in many mathematical situations. With such tricks, it is usually difficult, and in any case not desirable, to formalize them as lemmas: if you try to do so then almost certainly your formal lemma will not apply in all the situations where the trick does.
  • Of course, in many cases, the devil really is in the details, but nevertheless knowing the overall strategy of proof is extremely valuable when trying to read that proof.
  • Yong-Hui Says: November 3, 2008 at 5:57 pm | Reply I am in MSRI for the cofference discrete Rigity. Green will give the first lecture. I just happen to find a question for that tricki wiki: Whether is there a common-shared refference system for that tricki wiki? Similar to that of Mathscinet of ams math review It will be a basic instrument for a mathematical website.
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