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Tutorials in Physics Sense-Making: Tutorials work on building concepts and developing physical intuition that relates their everyday experience.

Photo caption: This is a streetcar in New Orleans traveling back towards The Quarter on St. Charles Ave. I held the camera against the window sill, making sure to divide the image equally between the inside and the outside. Shot with a Nikon D700 at .8 sec @ f/20, ISO 400, Nikkor 18.0-35.0mm f/3.4-4.5 lens set at 23mm. This photo was submitted to National Geographic's 2012 Photo Contest (Places). Photographer Don Chamblee is 53 years old, and has enjoyed cameras all his life, but he didn't start to get serious until college. Now, at 53 years old, he takes photos professionally and works in stock and fine art photos. You can read more about Don at his website.

Carl Wieman's Sci Ed Initiative @ U British Columbia includes resources like: clicker question resources what U should know 'bout ...PI, ...Ed Research, ...making clicker questions, ...cognitive research

Carnegie Mellon Robotics Academy NXT Sensors Decision making loops

A fun simulation of springy objects. It's adictive. You can either make your own objects, or play with objects created by others.

A free, open-source concept-map making piece of software.

This is a form Shah requires his math students to use if they are request a reassessment on a skill.  It might be adaptable for quizzes.

Let's estimate he can push down with a force about a quarter of his weight. If he weighs 200 pounds, this would result in a force of 50 pounds, or 225 N. We also know that the force of friction (F) between his feet and the asphalt depends on the force with which he pushes down (N) and the "coefficient of kinetic friction"(μ) between the soles of his shoes, which we will assume are made of rubber, and the pavement. F = μN The μ between rubber and asphalt varies between 0.5 and 0.8. Let's assume a value of 0.7. Therefore, solving for stopping distance, we get: D = ½(2100kg)(18m/s)2/(0.7)(225N) = 2160 meters, or over 1.3 miles! The situation might be improved if he exerted his full 200 pounds, or 900 Newtons, of force against the ground. In that case: D = 1/2(2100kg)(18m/s)2/(0.7)(900N) = 540 meters (about a third of a mile) However, the amount of torque exerted on his ankles and knees might make that a problematic proposition.

Great video on harnessing wind power on a small scale. We could do a make and take with this.

Projects that can be adapted for high school engineering courses.