Best content in Chem 109H Fall 2009

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pH and pOH - 1 views

chemed.chem.wisc.edu/...pH-and-pOH-969.html

shared by YJ Choi on 29 Nov 09 - Cached

Taking the antilog of both sides, we have
- YJ Choi on 29 Nov 09
  
  Is there a typo in the following equation?
  
  <div class="cArrow"> </div><div class="cContentInner">Is there a typo in the following equation?</div>
  
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There is a very simple relationship between the pH and the pOH of an aqueous solution at 25°C. We know that at this temperature
- YJ Choi on 29 Nov 09
  
  Isn't the second "Kw" in the following equation redundant?
  
  <div class="cArrow"> </div><div class="cContentInner">Isn't the second "Kw" in the following equation redundant?</div>
  
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The Rate Equation - 2 views

chemed.chem.wisc.edu/...The-Rate-Equation-999.html

shared by YJ Choi on 19 Oct 09 - Cached

. In the figure the tangents at t = 15 shave been drawn
- YJ Choi on 19 Oct 09
  
  From "...tangents at t=15 SHAVE been drawn" to "...tangents at t=15 HAVE been drawn"
  
  <div class="cArrow"> </div><div class="cContentInner">From "...tangents at t=15 SHAVE been drawn" to "...tangents at t=15 HAVE been drawn"</div>
  
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We say that the order of the reaction with respect to component A is a, while the order with respect to B is b. The overall order of the reaction is a + b.
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When this happens the reaction is said to be zero order in H3O+, because (cH,sub>3O+</sub>)0 = 1
- YJ Choi on 19 Oct 09
  
  notation in parentheses should be fixed
  
  <div class="cArrow"> </div><div class="cContentInner">notation in parentheses should be fixed</div>
  
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ChemPaths UW-Madison on 25 Oct 09

Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it). Also: the correction for the first part is "tangents at t=15 s have been drawn" - don't forget your units!

<div class="cArrow"> </div><div class="cContentInner">Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it). Also: the correction for the first part is "tangents at t=15 s have been drawn" - don't forget your units!</div>

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Reaction Mechanisms - 3 views

chemed.chem.wisc.edu/...Reaction-Mechanisms-1438.html

shared by ChemPaths UW-Madison on 23 Oct 09 - Cached

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Chemistry 2009 - 2 views

nobelprize.org/...2009 Nobel Prize 2009

shared by John Moore on 07 Oct 09 - Cached

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Properties of Alkanes - 0 views

chemed.chem.wisc.edu/...roperties-of-Alkanes-1398.html chemistry

shared by ChemPaths UW-Madison on 29 Sep 09 - Cached

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Internet Explorer 8: Home page - 0 views

www.microsoft.com/...default.aspx browser upgrade IE

shared by ChemPaths UW-Madison on 14 Sep 09 - Cached

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The Covalent Bond - 0 views

chemed.chem.wisc.edu/...The-Covalent-Bond-1350.html

shared by ChemPaths UW-Madison on 14 Sep 09 - Cached

The orbital is centered between the two atoms, so electron density is highest there. Again, as said above, this reduced the total energy of the system, and electrons in this orbital will thus lead to a covalent bond between the two atoms. This orbital is referred to as a bonding orbital.b)With the LUMO molecular orbital of H2 there is zero electron density between the two hydrogen atoms. There is a node in the orbital exactly the two atoms.
- Michael Boykin on 14 Sep 09
  
  Isn't this a contradiction? The top portion says the highest density is between the two atoms, and the bottom part says there is zero electron density between the two atoms...
  
  <div class="cArrow"> </div><div class="cContentInner">Isn't this a contradiction? The top portion says the highest density is between the two atoms, and the bottom part says there is zero electron density between the two atoms...</div>
  
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- ChemPaths UW-Madison on 14 Sep 09
  
  In part (b), the question asks about the LUMO - or the Lowest (Energy) Unoccupied Molecular Orbital. It is where the 3rd electron would go, if you tried to put it into this molecule. Thus what the last sentence in this solution states: "If electrons occupied this orbital, it would lead to the dissolution of the covalent bond." Does that make sense?
  
  <div class="cArrow"> </div><div class="cContentInner">In part (b), the question asks about the LUMO - or the Lowest (Energy) Unoccupied Molecular Orbital. It is where the 3rd electron would go, if you tried to put it into this molecule. Thus what the last sentence in this solution states: "If electrons occupied this orbital, it would lead to the dissolution of the covalent bond." Does that make sense?</div>
  
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Precipitation Reactions and Solubility - 0 views

chemed.chem.wisc.edu/...ecipitation-Reactions-942.html preciptiation solubility chemistry

shared by ChemPaths UW-Madison on 14 Sep 09 - Cached

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Balancing Chemical Equations - 0 views

chemed.chem.wisc.edu/...g-Chemical-Equations-1233.html

shared by YJ Choi on 05 Sep 09 - Cached

2NaMnO4 + H2O2 + 3H2SO4 → 2MnSO2 + Na2SO4 + 3O2 + 4H2O
- YJ Choi on 05 Sep 09
  
  Shouldn't the coefficient on Oxygen gas on the product side be a "10" instead of a "3"?
  
  <div class="cArrow"> </div><div class="cContentInner">Shouldn't the coefficient on Oxygen gas on the product side be a "10" instead of a "3"?</div>
  
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2NaMnO4 + H2O2 + 3H2SO4 → 2MnSO2 + Na2SO4 + 6O2 + 4H2O
- YJ Choi on 07 Sep 09
  
  I counted 22 Oxygen atoms on the reactant side, and so shouldn't the red "6" be a "5" to equal 22 Oxygen atoms on the product side? (Sorry to bother the editor again)
  
  <div class="cArrow"> </div><div class="cContentInner">I counted 22 Oxygen atoms on the reactant side, and so shouldn't the red "6" be a "5" to equal 22 Oxygen atoms on the product side? (Sorry to bother the editor again)</div>
  
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ChemPaths UW-Madison on 07 Sep 09

Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it). Also - the correction would be for the red 3 to become a 6 (not a 10 as you mentioned).

<div class="cArrow"> </div><div class="cContentInner">Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it). Also - the correction would be for the red 3 to become a 6 (not a 10 as you mentioned).</div>

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ChemPaths UW-Madison on 08 Sep 09

Thanks for following up on this. Apparently the Optical Character Recognition software missed the fact that this equation should be written with "SO4" not "SO2" anions - thus the original coefficient was correct. The sulfate subscripts have been changed and the original coefficient of "3" has been reinstated to its proper place. Thanks again.

<div class="cArrow"> </div><div class="cContentInner">Thanks for following up on this. Apparently the Optical Character Recognition software missed the fact that this equation should be written with "SO4" not "SO2" anions - thus the original coefficient was correct. The sulfate subscripts have been changed and the original coefficient of "3" has been reinstated to its proper place. Thanks again.</div>

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The Nature of Electromagnetic Radiation - 0 views

chemed.chem.wisc.edu/...romagnetic-Radiation-1391.html

shared by YJ Choi on 07 Sep 09 - Cached

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Atomic Structure and Isotopes - 0 views

chemed.chem.wisc.edu/...ructure-and-Isotopes-1217.html

shared by YJ Choi on 07 Sep 09 - Cached

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Using Chemical Equations in Calculations - 0 views

chemed.chem.wisc.edu/...ions-in-Calculations-1207.html

shared by YJ Choi on 06 Sep 09 - Cached

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Equations and Mass Relationships - 0 views

chemed.chem.wisc.edu/...d-Mass-Relationships-1209.html

shared by YJ Choi on 06 Sep 09 - Cached

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Analysis of Compounds - 0 views

chemed.chem.wisc.edu/...nalysis-of-Compounds-1210.html

shared by YJ Choi on 06 Sep 09 - Cached

A combustion train. H2O and C2O, produced by combination of O2 with H and C in the sample, are selectively absorbed by tubes containing Dehydrite [Mg(ClO4)2•3H2O] and ascarite (NaOH on asbestos).
- YJ Choi on 06 Sep 09
  
  "CO2" instead of "C2O"
  
  <div class="cArrow"> </div><div class="cContentInner">"CO2" instead of "C2O"</div>
  
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ChemPaths UW-Madison on 07 Sep 09

Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it).

<div class="cArrow"> </div><div class="cContentInner">Thanks! This has been fixed - as such this highlight may not show up anymore (the text of the highlight has been changed, so Diigo won't be able to find it).</div>

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