Groovy - Regular Expressions - 0 views
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Groovy supports regular expressions natively using the ~"pattern" expression
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// lets create a regex Pattern def pattern = ~/foo/ assert pattern instanceof Pattern
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Groovy also supports the =~ (create Matcher) and ==~ (matches regex) operators.
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Since a Matcher coerces to a boolean by calling its find method, the =~ operator is consistent with the simple use of Perl's =~ operator, when it appears as a predicate (in 'if', 'while', etc.). The "stricter-looking" ==~ operator requires an exact match of the whole subject string.
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def matcher = "\$abc." =~ /\$(.*)\./ // no need to double-escape! assert "\\\$(.*)\\." == /\$(.*)\./ matcher.matches(); // must be invoked assert matcher.group(1) == "abc" // is one, not zero
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def m = "foobarfoo" =~ /o(b.*r)f/ assert m[0][1] == "bar"
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// lets create a Matcher def matcher = "cheesecheese" =~ /cheese/ assert matcher instanceof Matcher answer = matcher.replaceAll("edam")
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// fancier group demo matcher = "\$abc." =~ "\\\$(.*)\\." matcher.matches(); // must be invoked [Question: is this still true? Not in my experience with jsr-04.] assert matcher.group(1) == "abc" // is one, not zero
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這裡需要特別注意的是，如果想要使用 matcher.group() 方法，那麼必須先執行 matcher.matches() 方法呼叫（我記得呼叫 find() 也行）。然而，如果是直接使用 groovy 的語法，那麼就可以直接使用 matcher[0][?] 的用法了！
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~"pattern" (create java.util.regex.Pattern)=~ (create java.util.regex.Matcher)==~ (do Matcher.matches() )